Error instantiating context 'spring.root' ??? Error with ressource

[winx]

Hi,

i'm new in using Spring ant want to get my first project running..

When want to compile it using VS2005, i always get the error:

Error instantiating context 'spring.root'.

the main looks like this:

IApplicationContext ctx = ContextRegistry.GetContext();

Lister.MovieLister ml = (Lister.MovieLister)ctx.GetObject("Lister");

foreach (Data.Movie ls in ml.moviesWith("willis"))
{
Console.WriteLine(ls.Title);
}



The app.config looks like this:

<?xml version="1.0" encoding="utf-8" ?>
<configuration>
<configSections>

<sectionGroup name="spring">

<section name="context" type="Spring.Context.Support.ContextHandler, Spring.Core"/>
<section name="objects" type="Spring.Context.Support.DefaultSectionHandler, Spring.Core" />

</sectionGroup>

</configSections>

<spring>

<context name="spring.root"> <!--HERE SHOULD BE THE ERROR-->

<resource uri="assembly://MovieSpringApp/MovieSpringApp.config/applicationcontext.xml"/>


</context>

</spring>

</configuration>


Could somebody explain me the error, and tell me how to use an special file for spring configuration...

this mean to change the ressource tag:

<ressource uri="assembly://...>
or
<ressource uri="file://...>


Thanks a lot,
winx

[Nop]

Hi winx!
Do not panic! :)
Your config file is ok except path assembly://MovieSpringApp/MovieSpringApp.config/applicationcontext.xml. Check this path. I think error behind it (Is applicationcontext.xml embeded resource?).
To use special file for spring configuration you need to replace
<resource uri="assembly://MovieSpringApp/MovieSpringApp.config/applicationcontext.xml"/> with <resource uri="~/applicationcontext.xml" />, for example.
It allows you change configuration without compilation.

Best regards,
Nop.

[winx]

Hi Nop,

the config file is in my assembly, in namespace MovieSpringApp.config.applicationcontext.xml and marked
as embedded.

I've also tried to use only the app.config with same settings,
except this:

<context name="spring.root">
<resource uri="config://spring/objects"/>
</context>

and included the <objects> secion in the app.config:

<?xml version="1.0" encoding="utf-8" ?>
<configuration>
<configSections>

<sectionGroup name="spring">

<section name="context" type="Spring.Context.Support.ContextHandler, Spring.Core"/>
<section name="objects" type="Spring.Context.Support.DefaultSectionHandler, Spring.Core" />

</sectionGroup>

</configSections>

<spring>

<context name="spring.root">

<resource uri="config://spring/objects"/>


</context>

<objects xmlns="http://www.springframework.net" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.net http://www.springframework.net/xsd/spring-objects.xsd">

<object id ="Finder" type="MovieSpringApp.Finder.MovieFinder, MovieSpringApp"/>

<object id="Lister" type="MovieSpringApp.Lister.MovieLister, MovieSpringApp">
<property name="Finder" ref="finder"/>
</object>

</objects>


</spring>

</configuration>

i've tried this, but got the same problem...

do you have another idea?

I think of en VS2005 configuration error, or something like this...

Thanks a lot,
winx

[Bruno Baia]

Hi,

please see the full stack trace and find inner exceptions to get more infos.


About resource handlers, see reference documentation :
Chapter 6. The IResource abstraction (http://www.springframework.net/doc-latest/reference/html/resources.html#d0e4802)


file://~/objects.xml
file://objects.xml
file:///C:/Temp/objects.xml



Bruno

[winx]

Hi,

i'll try this.

I used the same app.config in another spring application and: it works!!!

<?xml version="1.0" encoding="utf-8" ?>
<configuration>
<configSections>

<sectionGroup name="spring">

<section name="context" type="Spring.Context.Support.ContextHandler, Spring.Core"/>
<section name="objects" type="Spring.Context.Support.DefaultSectionHandler , Spring.Core" />

</sectionGroup>

</configSections>

<spring>

<context name="spring.root">

<resource uri="config://spring/objects"/>


</context>

<objects xmlns="http://www.springframework.net" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.net http://www.springframework.net/xsd/spring-objects.xsd">

</object>

</objects>

</spring>

</configuration>

But if if copied it back to my application, the error occurs again.
Is there something about renaming the MovieApp.exe.config or changing something else inside or outside the project???

Thx

[Bruno Baia]

Hi,


<context name="spring.root">

"spring.root" is the default context name, you don't need to specify it.



<objects xmlns="http://www.springframework.net" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.net http://www.springframework.net/xsd/spring-objects.xsd">

</object>

</objects>

What is doing the </object> tag here ?
you can simplify this with :

<objects xmlns="http://www.springframework.net">

</objects>


To get intellisense, be sure the spring-objects.xsd is installed into VS.
See reference documentation about this :
Chapter 24. Visual Studio.NET Integration (http://www.springframework.net/doc-latest/reference/html/vsnet.html)


<object id ="Finder" type="MovieSpringApp.Finder.MovieFinder, MovieSpringApp"/>

<object id="Lister" type="MovieSpringApp.Lister.MovieLister, MovieSpringApp">
<property name="Finder" ref="finder"/>

to get this working, you need to have MovieSpringApp.exe and MovieSpringApp.exe.config in your bin directory.
You don't need to rename the .config file, "app.config" is automatically renamed to "<assemblyname>.exe.config".

HTH,
Bruno

[winx]

Hi,

thanks for your answer.

I've now founded he problem, it's located here:

<objects xmlns="http://www.springframework.net">

<object id ="Finder" type="MovieSpringApp.Finder.MovieFinder, MovieSpringApp"/>

<object id="Lister" type="MovieSpringApp.Lister.MovieLister, MovieSpringApp">
<property name="Finder" ref="finder"/>
</object>

</objects>

In the source Code, the property is written like this: Finder

I've changed this and the problem is solved :)

Thanks a lot...

Now i'm trying to integrate hibernate.net into my system

Greets,
winx